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-Lovekush Kumar
"No" it is has only unit (steradian) not DF
Approach=
Step 1. formula- solid angle is the ratio of area of segment to the square of radius of the sphere of which the segment is a part
Step 2. DF of each paramter in the formula, as area and square of radius both are a type of length square or in other words "both" have dimension of length square so their ratio becomes dimensionless.
Following notations / inferences (right side) may be written / considered when you read the lines below (left side)
Uniform linear motion a=0
started from rest u=0
comes to rest v=0
stopped v=0
pentrated through distance x and stopped v=0
straight line and unidirectional speed=velocity (magnitude)
vertically upward motion u and g opposite sign
vertically downward motion u and g same sign
higher slope of x-t graph higher velocity
displacement in 5th second dispacement in 5 second - displacement in 4 second
constant velocity graph between v & t will be a line paralled to time axis.
Area under v-t graph Displacement as x=vt
Following step by step method may be followed for solving NEW physics numericals:
Step 1- P- M i.e. Physics to maths, write given values with thier NOTATION
e.g. if acceleration is given as 5 meter per second sqaure then wrtite a=5 ms-2 , time 2 sec as t=2s
Step-2 H-M i.e hidden to maths, write hints and indirect statement by identifying correct notation
e.g. if it is given that body was initialy at rest or started from rest then write u=0
Please note- Convert all given values in MKS system (or any other single system of units) before calculation
Step-3 TF/DF/CF, topic formula/desired formula/chapter formula
now decide which formula is to be utilised for desired quantity like if final velocity v is asked then look for formula "having" v,u,a and t (given and asked)
if you are unable to pick suitable formula then write chapter formula(main formula of a chapter) then look how can you find the quantities involved in the formula, for example if change in momentum is asked then find mass(m) using given data (mass may be given by the hint that force of 10 N produces accelration of 2 m per second sqaure then it will simply mean that mass is 5 kg)
In above case two formulas are utilised so correlation is done in step-4
Step-5 put values and solve neatly.